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30-包含min函数的栈

题目描述

https://leetcode.cn/problems/bao-han-minhan-shu-de-zhan-lcof

定义栈的数据结构,请在该类型中实现一个能够得到栈的最小元素的 min 函数在该栈中,调用 min、push 及 pop 的时间复杂度都是 O(1)。

示例:

MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.min();   --> 返回 -3.
minStack.pop();
minStack.top();      --> 返回 0.
minStack.min();   --> 返回 -2.

提示:

各函数的调用总次数不超过 20000 次

注意:本题与主站 155 题相同:https://leetcode.cn/problems/min-stack/

思路分析

实现代码

csharp
public class MinStack {

    private Stack<int> stack = new Stack<int>();
    private Stack<int> minStack = new Stack<int>();
    private int minValue = Int32.MaxValue;

    /** initialize your data structure here. */
    public MinStack() {

    }
    
    public void Push(int x) {
        stack.Push(x);
        minValue = minValue > x ? x : minValue;
        minStack.Push(minValue);
    }
    
    public int Pop() {
        minStack.Pop();
        minValue = minStack.Count == 0 ? Int32.MaxValue : minStack.Peek();
        return stack.Pop();
    }
    
    public int Top() {
        return stack.Peek();
    }
    
    public int Min() {
        return minValue;
    }
}

/**
 * Your MinStack object will be instantiated and called as such:
 * MinStack obj = new MinStack();
 * obj.Push(x);
 * obj.Pop();
 * int param_3 = obj.Top();
 * int param_4 = obj.Min();
 */

Released under the MIT License.